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swat32
3 years ago
9

Can anyone help me solve this?​

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
8 0

\\ \rm{:}\rightarrowtail sin^245°-tan^260°+cos^290°

  • sin45=1/√2
  • tan60=√3
  • cos90=1

\\ \rm{:}\rightarrowtail (\dfrac{1}{\sqrt{2}})^2-(\sqrt{3})^2+(0)^2

\\ \rm{:}\rightarrowtail \dfrac{1}{2}-3+0

\\ \rm{:}\rightarrowtail 1/2-3

\\ \rm{:}\rightarrowtail -5/2

Likurg_2 [28]3 years ago
3 0

Answer:

  • - 2.5

Step-by-step explanation:

  • sin²45° - tan²60° + cos²90° =
  • (√2/2)² - (√3)² + 0² =
  • 1/2 - 3 + 0 =
  • 0.5 - 3 =
  • - 2.5
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= x^2 - 9 \\\\= x^2 - 3^2 \\\\ \red{= (x+3)(x-3)} \qquad\bf [Using \ a^2-b^2 = (a+b)(a-b) ]

<u>Factorising</u><u> </u><u>3x</u><u>³</u><u> </u><u>+</u><u> </u><u>8</u><u>1</u><u> </u>

= 3x^3 + 81\\\\= 3(x^3+27) \\\\= 3( x^3+27) \\\\ = 3(x^3+3^3) \\\\ \red{= 3 [ (x+3)(x^2+9-3x) ] } \qquad \bf{[ Using \ a^3+b^3=(a+b)(a^2+b^2-ab) ] }

Hence we can see that (x+3) is common factor in both expressions.

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8 0
3 years ago
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The figure is attached below

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