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bonufazy [111]
3 years ago
14

I really want to know what 87x73 is showing work.

Mathematics
1 answer:
kumpel [21]3 years ago
8 0
87 x 73 = 6,351
2
87
x 73
____
1
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QUESTION A

The given multiplication problem is

\frac{39}{64} \times \frac{8}{13}

Factor each term to obtain;

\frac{13\times 3}{8\times8} \times \frac{8}{13}

Cancel out the common factors to obtain;

\frac{1\times 3}{8\times1} \times \frac{1}{1}

Simplify to get;

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QUESTION B

The given multiplication problem is

\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}

This the same as

\frac{2\times 1\times 4}{3\times 5\times 7}

This simplifies to;

\frac{8}{105}

QUESTION C

The given problem is

\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}

This is the same as

\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}

=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}

This simplifies to

=\frac{1}{4}

QUESTION D.

The given expression is

\frac{4}{9}\times 54

Factor the 54 to obtain;

\frac{4}{9}\times 9\times 6

Cancel the common factors to get;

\frac{4}{1}\times 1\times 6

This simplifies to;

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The given problem is

20\times 3\frac{1}{5}

Convert the mixed numbers to improper fraction to obtain;

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=4\times5 \times \frac{16}{5}

Cancel the common factors to get;

=4\times1 \times \frac{16}{1}

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The multiplication problem is

11 \times 2 \frac{7}{11}

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11 \times \frac{29}{11}

Cancel out the common factors to get;

=1 \times \frac{29}{1}

Simplify;

=29

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The given problem is

5\frac{1}{3}\times 5\frac{1}{8}

Convert to improper fractions;

=\frac{16}{3}\times \frac{41}{8}

Cancel out the common factors to get;

=\frac{2}{3}\times \frac{41}{1}

=\frac{82}{3}

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=27\frac{1}{3}

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The given expression is

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\frac{32}{3} \times \frac{11}{8}

Cancel common factors to get;

=\frac{4}{3} \times \frac{11}{1}

Simplify

=\frac{44}{3}

Convert back to mixed numbers;

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