I need help in algebra
2 answers:
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Answer:
Step-by-step explanation:
Given a ΔLMN.
Line LN is extended to point O.
such that:
and
To find:
Solution:
Kindly refer to the attached image for the given triangle and dimensions of angles.
Let us recall the external angle property of a triangle:
The external angle of a triangle is equal to the sum of two opposite internal angles.
i.e.
Putting the value of in
.
Start by using trig to find the length of the line LJ
The triangle KJL (big right angled triangle) has been given the following dimensions
Hypotenuse =
The adjacent angle is 30 degrees
Since we have the hypotenuse and the angle we must use the equation
opposite = Sin(angle) x Hypotenuse
Opposite= sin30 x
Opposite=
Therefore line LJ is
Now look at the smaller right angled triangle (LMJ)
Hypotenuse is the line LJ which is
The adjacent angle is 45
Since we have hypotenuse and angle we must use the equation opposite = sin(angle) * h
therefore
x= * sin45= 4
The triangle KJL (big right angled triangle) has been given the following dimensions
Hypotenuse =
The adjacent angle is 30 degrees
Since we have the hypotenuse and the angle we must use the equation
opposite = Sin(angle) x Hypotenuse
Opposite= sin30 x
Opposite=
Therefore line LJ is
Now look at the smaller right angled triangle (LMJ)
Hypotenuse is the line LJ which is
The adjacent angle is 45
Since we have hypotenuse and angle we must use the equation opposite = sin(angle) * h
therefore
x=