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3 years ago

3y squared minus 2y minus y squared minus y

Mathematics

1 answer:

Maslowich3 years ago

4 0

Answer:

3y^2-2y-y-y

Step-by-step explanation:

3y^2-2y-2y

3y^2-4y

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For the upcoming holiday season, Dorothy wants to mold 20 bars of chocolate into tiny pyramids. Each bar of chocolate contains 6

gizmo_the_mogwai [7]

So each bar contains 6 and she has 20 so 6 times 20=120

pyramid volume=legnth times width times height times 1/3
v=base times height times 1/2
v=1 times 2 times 1/3
v=2/3
volume of 1 pyramid is 2/3 cubic inches

divide 120 by 2/3 to find out how many pyrimds will fit into amount given
120/1 divide by 2/3=120/1 times 3/2=360/2=180

she can make 180 pyramids

3 0

3 years ago

Read 2 more answers

Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra

katen-ka-za [31]

You made a mistake with the probability $p_{j}$ , which should be $p_{i}$ in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer $j$ , is given by:

(1) $\frac{p_{j} }{1-d_{i}p_{i} } , if j \neq i,$ and

(2) $\frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} } , if j = i.$

so we can say:

$A$ is the event that you search drawer $i$ and find nothing,

$B$ is the event that you search drawer $i$ and find the paper,

$C_{k}$ is the event that the paper is in drawer $k, k = 1, ..., n.$

this gives us:

$P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}$

$P(A) = 1 - P(B) = 1 - d_{i} p_{i}$

Solution to Part (1):

if $j \neq i$ , then $P(A \cap C_{j} ) = P(C_{j} )$ ,

this means that

$P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)} = \frac{P(C_{j} )}{P(A)} = \frac{p_{j} }{1-d_{i}p_{i} }$

as needed so part one is solved.

Solution to Part(2):

so we have now that if $j$ = $i$ , we get that:

$P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}$

remember that:

$P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}$

this implies that:

$P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )$

so we just need to combine the above relations to get:

$P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }$

as needed so part two is solved.

8 0

3 years ago

Jeff saved 33 more nickels than dimes. He had 4 times as many nickels as dimes. How much did he save in all

AlexFokin [52]

Answer:

He saved $3.30 in all.

7 0

3 years ago

2 wholes and 3/12 + 3/? = 2 wholes and 5/8 .what is the missing number ?

Sladkaya [172]

Basically you know that the 2 wholes from both sides cancel out.

Set up the equation, 5/8 = 3/12 + 3/x

3/x = 5/8 - 3/12

Set them to have a common denominator, 3/x = 15/24 - 6/24

3/x = 9/24

Simplify 9/24 and you will get 3/8

3/x = 3/8

Obviously this means x = 8

6 0

3 years ago

Please, can someone help?

LekaFEV [45]

The area of that figure is 2453.25 square feet

First, you would need to find the area of the rectangle

(L)(W)
(70)(30)
2100

Then since it is only a semi circle, the formula is pi*r^2/2

You find the area of a full circle first

(3.14)(15^2)
(3.14)(225)
706.5

Then you divide that by 2 since it’s only half a circle

706.5/2 = 353.25

Finally you add that by the area of the rectangle

2100 + 353.25 = 2453.25 square feet

3 0

4 years ago

3y squared minus 2y minus y squared minus y​

3y squared minus 2y minus y squared minus y