The answer for your question is c
Answer:
c
Step-by-step explanation:
Answer:
k= -29
Step-by-step explanation:
Answer:
C. H(x) = 2x+6
Step-by-step explanation:
Volume of the cylindrical silo = Area of its circular base × Height
Volume of the cylindrical silo = πr²×H
If the area of the circular base of the silo is given by the function A(x), the volume is given by C(x) and the height is given by H(x), the formula can be expressed as;
C(x) = A(x) × H(x)
The height of the cylindrical silo will be;
H(x) = C(x)/A(x)
Given C(x) = 6.28x³ + 18.84x² and
A(x) = 3.14x²
H(x) = 6.28x³ + 18.84x²/3.14x²
H(x) = x²(6.28x+18.84)/3.14x²
H(x) = (6.28x+18.84)/3.14
H(x) = 3.14(2x+6)/3.14
H(x) = 2x+6
Hence, the function, H(x) that represents the height of the silo is 2x+6.
The orientation of the solid is odd, but here is what I see.
24+24+39+52+65= 204 units^2
