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3 years ago

ZE and ZF are vertical angles with mZE = 8x + 8 and mZF = 2x +38. What is the value of x?

Mathematics

2 answers:

Dovator [93]3 years ago

7 0

Answer:

Since ZE and ZF are vertical angles, they are congruent.

8x+8 = 2x+38

8 = 2x-8x+38

8 = -6x+38

8-38 = -6x

-30 = -6x

x = -30/-6

x = 5

mash [69]3 years ago

3 0

Answer:

x = 5

Step-by-step explanation:

Vertical angles are congruent, so ...

∠E = ∠F

8x +8 = 2x +38

6x = 30 . . . . . . . . . subtract (2x+8)

x = 5 . . . . . . . . . . . divide by 6

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$8t^2 -48 t -7=0$

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If the question is: When will the object hit the ground at when the time is how many seconds?

We have the function for the heigth given by:

$h(t) = -16t^2 +96 t +14$

And we want to find the time where $h(t) =0$ so we can set like this the condition:

$0 =-16t^2 +96 t +14$

And we can rewrite the expression like this:

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And we can use the quadratic equation to solve for t like this:

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a= 8, b =-48, c = -7 and replacing we got:

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