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3 years ago

Use scientific notation to calculate the exact number of hours in one year

Mathematics

1 answer:

Mrrafil [7]3 years ago

3 0

8.7 x 10^3

The total number of hours in one year is 8760

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Divide. Write your answer as a fraction or mixed number in simplest form. -4/5 divided by 16/15

ale4655 [162]

Answer:

-0.75

Step-by-step explanation:

6 0

3 years ago

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I think the answer is A Correct?

xeze [42]

You can see that there are 6 rock CDs, over a total of

$6+10+4+8+12 = 40$

So, the ratio of rock CDs over the total number of CDs is

$\dfrac{6}{40} = 0.15$

Which is 15%.

So, yes, the answer is A

4 0

3 years ago

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Can someone solve m - 4m= -6 step by step please?

marta [7]

Answer:

m = 2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define Equation

m - 4m = -6

Step 2: Solve for m

Combine like terms: -3m = -6
Divide -3 on both sides: m = 2

Step 3: Check

Plug in m into the original equation to verify it's a solution.

Substitute in m: 2 - 4(2) = -6
Multiply: 2 - 8 = -6
Subtract: -6 = -6

Here we see that -6 does indeed equal -6.

∴ m = 2 is the solution to the equation.

3 0

3 years ago

The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.

erma4kov [3.2K]

Answer:

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

$\\$

Step-by-step explanation:

Given:

Radius of the cylinder = 7 cm
Height of the cylinder = 10 cm

$\\$

To Find:

Curved surface area
Volume

$\\$

Solution:

$\\$

Using formula:

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA \: of \: cylinder = 2\pi rh}}}}}} \: \star \\ \\$

Substituting the required values: 

$\\$

$\dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times 22 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 44 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 440 \: {cm}^{2} \\ \\ \\$

Now,

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}= \pi {r}^{2} h}}}}}} \: \star \\ \\ \\$

Substituting the required values, 

$\\$

$\dashrightarrow \: \: \sf Volume {(cylinder)}= \dfrac{22}{7} \times {(7)}^{2} \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= \frac{22}{7} \times 49 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 1540 {cm}^{3} \\ \\ \\$