Let x be your first alloy
2/5x+7/10(30-x)=1/2(30)
4x+210-7x=150
3x=60
x=20
So, you need 20 lbs of the first alloy, and 10 parts of the second to make 30 lbs of half iron and half silver alloy!
The slope would be 1/17 and then you would use that slope and plug it into the y=mx+b and solve for b
Answer:
Margin of Error = 5.4088 ;
Confidence interval = (30.1 ; 40.9)
Interval estimate are almost the same
Step-by-step explanation:
Given that :
Population standard deviation, σ = 9.3
Sample size, n = 8
Xbar = 35.5
Confidence level = 90%
The confidence interval:
Xbar ± Margin of error
Margin of Error = Zcritical * σ/sqrt(n)
Zcritical at 90% = 1.645
Margin of Error = 1.645 * 9.3/sqrt(8) = 5.4088
Confidence interval :
Xbar ± Margin of error
35.5 ± 5.4088
Lower boundary = (35.5 - 5.4088) = 30.0912 = 30.1
Upper boundary = (35.5 + 5.4088) = 40.9088 = 40.9
(30.1 ; 40.9)
T distribution =. (30.5 ; 40.5)
Normal distribution = (30.1, 40.9)
Step 1- multiply 40 by 25 to get 1000
step2- multiply 8 by 5 to get 40
step3- divide 1000 by 4 to get 250
answer. 250 pieces
Answer:
m∠P = 143°
Step-by-step explanation:
We know that supplementary angles add up to 180, and with the knowledge that angle P is 5 times than 4 less (5x-4) the measure of angle Q (x), we can set up the equation (4x-5)+(x)=180. We can then solve and get x = 37, and then we can plug X back into 5x-4 to get the angle of 143 degrees.
