2y-x=3/4(-y+1)first distribute
2y-x=-3/4y+3/4 get the y on one side
2y-x+3/4y=3/4 add 3/4y to both sides
2y+3/4y=3/4+x add x to both sides
11/4y=3/4+x now divide by 11/4 (both sides)
y=3/11+4/11x
y=3+4x/11
choice c is the answer
Answer:
84 - c
Step-by-step explanation:
The correct expression would be 84 - c
Answer:
<h2>no real solution</h2>
Step-by-step explanation:
Answer:
option D 12 is correct..
in second question the student didn't multiply -3 with 4. that's the mistake he did.
hope it helps
First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)
To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0 x=-4 x=2
So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)
And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5
3 gets us 21
So now you know end behavior, zeroes, and signs of intervals
Hope this helps<span />
