Answer: ASA method must be applied to the given triangles to prove then congruent.
In two triangles, if two angles and their included side are congruent then the two triangles are said to be congruent .This method is known as Angle-Side -Angle postulate(ASA).
In the given triangles one side with their corresponding angles are equal. Therefore by ASA postulate they are congruent.
There we can see no other sides are given equal therefore all the other options cannot be applied.
you are lucky I had this test yesterday and I have the answer is ASA my math teacher said it was fine
Using: loga b = log b / log a
1) a=x+3, b=4 → y1=log4 (x+3) → y1= log (x+3) / log 4
2) a=2+x, b=2 →y2=log2 (2+x) → y2=log (2+x) / log 2
Answer:
y1=log (x+3) / log 4, y2= log (2+x) / log 2
Y=a(x-h)^2+k
is what vertex form look like. (h,k) is your vertex so in this problem your vertex would be (60,200)
(-5, 7) - Quadrant II
(8 1/2, -4) - Quadrant IV
(0,5) - y axis
Step-by-step explanation:
Answer:
as x tends to infinity y=infinity
as x tends to 1 y=infinity
x=1 vertical asymptote
