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serious [3.7K]
4 years ago
15

Population data from three towns is displayed in the tables below. which town has growth that shows an exponential model?

Mathematics
2 answers:
Vinil7 [7]4 years ago
7 0

Answer:

Option C is correct.

Step-by-step explanation:

We have been given the three different datas

We will check for their growth rate.

\frac{a_2}{a_1}

In case of Roseville.

\frac{108}{72}=1.5

In case of Smithton.

\frac{120}{78}=1.53

In case of Travis.

\frac{160}{107}=1.49

So, the rate is high in case of Travis

Therefore, option C is correct.

inessss [21]4 years ago
6 0

Answer:

The correct option is A.

Step-by-step explanation:

From the given tables we can find he rate of change.

In Roseville town,

The change in population in first 10 years is

108-72=36

The change in population in second 10 years is

162-108=54

The rate of change of Roseville is not constant, therefore the first function represents a exponential function.

In Simthton town,

The change in population in first 10 years is

120-78=42

The change in population in next 10 years is

162-120=42

The rate of change of Simthton town is constant, therefore the second table represents a linear function.

In Travis town,

The change in population in first 10 years is

160-107=53

The change in population in next 10 years is

213-160=53

The rate of change of Travis town is constant, therefore the third table represents a linear function.

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Which table shows a proportional relationship between X and Y?
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Answer:

Table 3

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Y. 50,150,200,250

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

<u><em>Verify each table</em></u>

Find the value of k for each ordered pair

If the value of k is the same for all ordered pairs, then the table represents a proportional relationship.

If the k-value is different for any of the ordered pairs, then the table does not represent a proportional relationship

<em>Table 1</em>

For x=2, y=6 ---> k=\frac{y}{x} ----> k=\frac{6}{2}=3

For x=4, y=12 ---> k=\frac{y}{x} ----> k=\frac{12}{4}=3

For x=5, y=18 ---> k=\frac{y}{x} ----> k=\frac{18}{5}=3.6

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<em>Table 2</em>

For x=3, y=1.5 ---> k=\frac{y}{x} ----> k=\frac{1.5}{3}=0.5

For x=5, y=2.5 ---> k=\frac{y}{x} ----> k=\frac{2.5}{5}=0.5

For x=7, y=3 ---> k=\frac{y}{x} ----> k=\frac{3}{7}=0.4

The values of k are different

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<em>Table 3</em>

For x=1, y=50 ---> k=\frac{y}{x} ----> k=\frac{50}{1}=50

For x=3, y=150 ---> k=\frac{y}{x} ----> k=\frac{150}{3}=50

For x=4, y=200 ---> k=\frac{y}{x} ----> k=\frac{200}{4}=50

For x=5, y=250 ---> k=\frac{y}{x} ----> k=\frac{250}{5}=50

The values of k are the same

therefore

The table 3 represent a proportional relationship

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For x=1, y=1.5 ---> k=\frac{y}{x} ----> k=\frac{1.5}{1}=1.5

For x=2, y=3 ---> k=\frac{y}{x} ----> k=\frac{3}{2}=1.5

For x=3, y=6 ---> k=\frac{y}{x} ----> k=\frac{6}{3}=2

The values of k are different

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