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pickupchik [31]
3 years ago
6

A rectangle has a length that is increasing at a rate of 10 mm per second with the width being held constant. What is the rate o

f change of the area of the rectangle if the width is 8 mm?
Mathematics
1 answer:
NISA [10]3 years ago
6 0

Answer:

the rate of change of the area is Ra= 80 mm² per second

Step-by-step explanation:

the area of a rectangle (A) is

A = L * W , L= length and W= width

if the width remains constant the change in the area is only due to the change in length , thus:

ΔA = Δ( L * W ) = W * ΔL , where ΔA represents the change in area and ΔL represents the change in length

ΔA = W ΔL

denoting Δt as the time required to change, and dividing both sides by Δt

ΔA/Δt = W ΔL/Δt

where Ra=ΔA/Δt = rate of change of the area and RL=ΔL/Δt rate of change of the length.

thus

Ra = W * RL

replacing values

Ra = W * RL = 8 mm * 10 mm/second = 80 mm² /second

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A triangle has a perimeter of 48 feet. If the three sides of the triangle are n, 4n−2, and 4n−4, what is the length of each side
alexdok [17]

Answer:

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