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Ne4ueva [31]
3 years ago
13

Write an equation that gives the proportional relationship of the graph. A) y = 1 8 x B) y = 8x C) y = 9x D) y = 72x

Mathematics
2 answers:
Marysya12 [62]3 years ago
4 0

Here graph of an equation given.

The co-ordinates in the graph given are (0,0), (9,72), (18,144), (36,288), (45,360).

(0,0) point means, for x =0, y=0

(9,72) point means, for x =9, y=72

(18,144) means, for x =18, y=72

(36,288) means, for x = 36, y=288

(45,360) means, for x = 45, y =360.

We know that, (0)(8) = 0, (9)(8) = 72, (18)(8) = 144, (36)(8) = 288, (45)(8) = 360,

That means in each point, y value is 8 times the x value.

That means, we can write the equation as y=8x which also shows the proportional relationship of the graph.

So we have got the required answer.

The required equation is y=8x.

exis [7]3 years ago
3 0
For this case we must find a function of the form:
 y = mx + b

 Where,
 m: slope of the line
 b: cutting point with the y axis.
 We note that the cutoff point with the y axis occurs at 0.
 Therefore we have:
 b = 0

 On the other hand, the slope of the line is given by:
 m =  \frac{y2-y1}{x2-x1}
 Substituting values we have:
 m = \frac{72-0}{9-0}
 Rewriting:
 m = \frac{72}{9}
 m = 8
 Then, replacing values the equation of the line is:
 y=8x
 Answer:
 
y=8x
 B) y = 8x
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Answer:

18

Step-by-step explanation:

6*2=12

9*2=18

Two laps per minute

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Salena, Justin, and Brandon were riding their bikes to the library after school. The library is 12 1/2 miles from school. Salena
faust18 [17]

Answer:

Salena's got to the library first

Step-by-step explanation:

12½ miles = 25/2 miles

2½ miles = 5/2 miles

5¾ miles = 23/4 miles

114 miles = 114 miles

Salena's time of arrival =

if 5/2 miles : 5 minutes

then 25/2 miles : ?

25/2 ÷ 5/2. × 5

25/2 × 2/5 × 5

25 minutes

Justin 's time of arrival=

if 23/4 miles : 12 minutes

25/2 miles : ?

25/2 ÷ 23/4 ×12

25/2 × 4/23 ×12

26 minutes approximately

Brandon 's time of arrival=

if 114 miles : 258 minutes

25/2 miles : ?

25/2 ÷114 ×258

25/2 × 1/114×258

25 × 1/57 × 258

113 minutes approximately

3 0
3 years ago
On a coordinate plane, a circle has a center at point (negative 6, 4). What is the equation of the circle shown in the graph? (
lukranit [14]

Answer:

1) x+6 2)y-4 3)36

Step-by-step explanation:

(x+6)² + (y-4)² = 36

5 0
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Juan wrapped 2 presents every 16 hours. At that rate, how long, in
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Since it took Juan 16 hours to wrap 2 presents, it will take Juan 32 hours.

1 present- 8 hours

2 present- 16 hours

3 present- 24 hours

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2 years ago
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A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so
Debora [2.8K]

Let A(t) = amount of salt (in pounds) in the tank at time t (in minutes). Then A(0) = 11.

Salt flows in at a rate

\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}

and flows out at a rate

\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}

which I'll solve with the integrating factor method.

\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95

-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}

\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}

Integrate both sides. By the fundamental theorem of calculus,

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)

\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}

\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}

\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}

After 1 hour = 60 minutes, the tank will contain

A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131

pounds of salt.

7 0
2 years ago
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