Ask question

Ask question

All categories

Ray Of Light [21]

3 years ago

11

for the past five months kaias gift shop had these profits or losses $120, $85, -$35 and 40$ what was her average profit or loss

for these five months

1 answer:

Montano1993 [528]3 years ago

7 0

Average amount is 52.5

You might be interested in

A rocket is launched from the top of a 76-foot cliff with an initial velocity of 135 ft/s.a. Substitute the values into the vert

mixas84 [53]

You divide -16 by 76 and then mutiply your answer by the number you got

3 0

4 years ago

Read 2 more answers

Problem 1: Given the following probabilities P(Ac) = 0.45, P(B) = 0.34, and P(B|A) = 0.23. Find the following probabilities:

-BARSIC- [3]

Answer:

P(A)=0.55

P(A and B)=P(A∩B)=0.1265

P(A or B)=P(A∪B)=0.7635

P(A|B)=0.3721

Step-by-step explanation:

P(A')=0.45

P(A)=1-0.45=0.55

P(B∩A)=?

P(B|A)=0.23

P(B|A)=(P(A∩B))/P(A)

0.23=(P(A∩B))/0.55

P(A∩B)=0.23×0.55=0.1265

P(A∪B)=P(A)+P(B)-P(A∩B)

=0.55+0.34-0.1265

=0.7635

P(A|B)=[P(A∩B)]/P(B)=0.1265/0.34 ≈0.3721

8 0

3 years ago

Find the value of a1 for an infinite geometric series with S=12 and r=1/6

blondinia [14]

$S_n=a(1+r+\cdots+r^{n-1}+r^n)$
$rS_n=a(r+r^2+\cdots+r^n+r^{n+1})$
$(1-r)S_n=a(1-r^{n+1})$
$S_n=a\dfrac{1-r^{n+1}}{1-r}$

When $|r|$ , we have

$\displaystyle\lim_{n\to\infty}S_n=\dfrac a{1-r}$

as is the case here. Since $S=\lim\limits_{n\to\infty}S_n=12$ and $r=\dfrac16$ are given, we can find the first term $a$ immediately:

$12=\dfrac a{1-\frac16}\implies12=\dfrac65a\implies a=10$

6 0

3 years ago

(っ◔◡◔)っ ♥ f me ♥ please please please please <3

harina [27]

Answer:

No

Step-by-step explanation:

5 0

3 years ago

Find the probability of spending a 5 and rolling a 1, 2 or 3.

Deffense [45]

B because they all have an equal chance

7 0

3 years ago