All categories

2 years ago

What is a point-slope equation of the line with slope -12 that goes through the point (5,3)?

Mathematics

2 answers:

masya89 [10]2 years ago

6 0

Step-by-step explanation:

Equation of a straight line is given by Y=MX+C

GIVEN POINTS (5, 3) and gradient -12, therefore

in the form of y=mx+c to get the constant, it will be 3=-12(5)+c

3=-60+c

3+60=c

c=63

y=mx+c

y=-12x+63

11Alexandr11 [23.1K]2 years ago

5 0

The answer should be either B or D im not sure on the graphing part but both B and D equal -12

You might be interested in

Solve the equation. y 3 = –y 9 y = 1 y = 3 y = 6 y = 9

GaryK [48]

The solution of the equation is y = 3.

<h3>What is the linear equation?</h3>

An equation between two variables that gives a straight line when plotted on a graph.

The solution to the equation is;

$\rm y + 3 = -y + 9\\\\y+y=9-3\\\\2y=6\\\\y=\dfrac{6}{2}\\\\y=3$

Hence, the solution of the equation is y = 3.

To know more about linear equations click the link given below.

brainly.com/question/14824234

7 0

2 years ago

10 apples for $3.50. How much is the cost per apple?

Tomtit [17]

Answer:35 cents per apple.

Step-by-step explanation:

3.50/10=0.35

5 0

2 years ago

Section 5.2 Problem 6: Find the general solution <img src="https://tex.z-dn.net/?f=y%27%27%20%2B%206y%27%20%2B%2010y%2

mihalych1998 [28]

Answer:

$y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Step-by-step explanation:

Given Second-Order Homogenous Differential Equation

$y''+6y'+10y=0$

Use Auxiliary Equation

$m^2+6m+10=0\\\\(m+3)^2+1=0\\\\(m+3)^2=-1\\\\m+3=\pm i\\\\m=-3\pm i$

General Solution

$y=e^{pt}(A\: cos\: qt+B\:sin\:qt)\\\\y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Note that the DE has two distinct complex solutions $p\pm qi$ where $A$ and $B$ are arbitrary constants.

4 0

1 year ago

(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounde

monitta

Using the distance formula, $d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2 } \\$ , what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?

Using the points given, plug them into the equation.

$d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2 } \\d = \sqrt{((4) - (-2))^2 + ((4) - (2)^2 } \\d=\sqrt{(4+2)^2 + (4-2)^2}\\d=\sqrt{(6)^2 + (2)^2} \\d=\sqrt{36+4} \\d=\sqrt{40} \\$

Plug this into a calculator and you get 6.32455532

Since you only need it up to the tenth (0.1), round up 6.32

Five or more, let it soar. Four or less, let it rest.

Since two is lower than four, we drop it.

Therefore, the distance between points (-2, 2) and (4, 4) is 6.3

Hope this helps ^w^

8 0

2 years ago

Question is in picture

Papessa [141]

Answer:

casino see v

Step-by-step explanation:

j:)

8 0

2 years ago