Answer:
A is
Step-by-step explanation:
The answer is
A. No, because 1 x-value corresponds to 2 different y-values
Answer:
1/ 3
Step-by-step explanation:
If each of the cards is turned over, the probability of picking up a card of one type P(E) becomes equal to:
=> P(E) = number of cards of the required type/ total number of cards
● Total number of spades( ♤ ) = 3
{the queen, one ace and the nine are all spades}
● Total number of cards = 6
Probability of drawing a spade= 3/ 6
= 1/ 2
● Total number of "7" = 1
● Total number of cards = 6
Probability of drawing a 7
= 1/ 6
Now, what's asked is the difference in the probabilities of drawing a spade and a seven.
= 1/ 2 - 1/ 6
= 3/ 6 - 1/ 6
= 2/ 6
= 1/ 3
Hence, 1/ 3 of a greater chance of drawing a spade over a 7.
Is your question true or false?
2abc - 3ab = -30? if a =2, b = -3 and c= 4
plug in
2(2)(-3)(4) - 3(2)(-3) = -30
Simplify
-48 + 18 = -30
-30 = -30
Both sides are equal so
It's true.
answer:
B. 2:6 is equal to 1:3
2 and 6 are both even so you can split both of them in half and you would get 1 and 3