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olasank [31]
3 years ago
13

If this number is larger than 6, then its square is larger than 36.The number is not larger than 6.therefore Its square is not l

arger than 36.a. Trueb. False
Mathematics
1 answer:
Anit [1.1K]3 years ago
6 0

Answer:

False

Step-by-step explanation:

If this number is larger than 6, then its square is larger than 36.

If x > 6, then x² > 36

The number is not larger than 6.therefore Its square is not larger than 36.

x ≤ 6; therefore, x² ≤ 36

-7 is < 6; however -7² > 36 as -7² = 49

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Write a simplified expression to find the perimeter of a square with a side length of 3y units.
Murrr4er [49]

Answer:

Perimeter= 12y units

3y(4) = 12y

Step-by-step explanation:

3y + 3y + 3y + 3y= 12y

4 0
2 years ago
Triangles A C B and M Q R are shown. Sides A B and M R are congruent. Angles C A B and M R Q are 42 degrees. Angle C B A is 53 d
miss Akunina [59]

By ASA postulate it can be say that the triangle ABC and triangle MRQ are congruent

<h3>What is Angle Sum Property?</h3>

The sum of all three angles(interior) of a triangle is 180 degrees, and the exterior angle of a triangle measures the same as the sum of its two opposite interior angles.

Using Angle Sum Property, in ΔMRQ

<M + <R + <Q= 180

<M + 42 + 85 = 180

<M = 180 -42

<M= 53°

Now, In ΔMRQ and ΔABC  

<A= <R ,

<B = <M

AB = MR

Hence, By ASA criteria ΔMRQ ≅ ΔABC  

Learn more about this concept here:

brainly.com/question/3486366

#SPJ1

4 0
1 year ago
Solve (-5/2)x ‐ 5 = -55
Dmitry_Shevchenko [17]

Answer: 5

Step-by-step explanation: add 5 on each side and you get -50 then divide -5/2 with -50 and get 5

5 0
3 years ago
Simplify 2√2-√3<br> ---------------<br> √2+√3
serious [3.7K]

Step-by-step explanation:

=  \frac{2 \sqrt{2}   -  \sqrt{3} }{ \sqrt{2} +  \sqrt{3}  }

=  \frac{2 \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} +  \sqrt{3}  }  \times  \frac{ \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} -  \sqrt{3}  }

= \frac{ 2( \sqrt{2}  -  \sqrt{3} )( \sqrt{2}  -  \sqrt{3} )}{ { \sqrt{2} }^{2} -  { \sqrt{3} }^{2}  }

=  \frac{2(2 -  \sqrt{6}  -  \sqrt{6} - 3) }{2 - 3}

=  \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}

=  \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}

= 2(1 + 2 \sqrt{6} )

= 2 + 4 \sqrt{6}

6 0
2 years ago
Prove that if b is a square matrix then b+b^t is symmetric
WARRIOR [948]
A matrix \mathbf X is symmetric if \mathbf X=\mathbf X^\top. We have

(\mathbf B+\mathbf B^\top)^\top=\mathbf B^\top+(\mathbf B^\top)^\top=\mathbf B^\top+\mathbf B=\mathbf B+\mathbf B^\top

and so \mathbf B+\mathbf B^\top is indeed symmetric.
6 0
3 years ago
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