$a_1=96;\ a_2=48;\ a_3=24;\ a_4=12;\ a_5=6\\\\a_1=a_2:2\to96:2=48\\a_2=a_3:2\to48:2=24\\a_3=a_2:2\to24:2=12\\a_4=a_3:2\to12:2=6\\\\therefore\\\\a_n=96:2^{n-1}=\frac {96}{2^{n-1}}\\\\check:\\a_1=\frac{96}{2^{1-1}}=\frac{96}{1^0}=96\\a_2=\frac{96}{2^{2-1}}=\frac{96}{2^1}=\frac{96}{2}=48\\a_3=\frac{96}{2^{3-1}}=\frac{96}{2^2}=\frac{96}{4}=24\\\vdots$

8 0

3 years ago

Which of the following ratios will form a proportion with 2/3

Olenka [21]

6/15 and 12/18 are ratios of 2/3

6 0

3 years ago

Read 2 more answers

You run 18 miles in 2 hours and 45 miles in 5 hours how fast are you running

Lesechka [4]

So let's find the unit rate of these.

18 mi/ 2 hrs = 9 mi/ 1hr

45 mi / 5 hrs = 9 mi/ 1 hr

So you are running 9 miles an hour.

If you have any questions please comment! :)

6 0

3 years ago

Read 2 more answers