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Serjik [45]
3 years ago
15

To go to dance class at 6:45p.m. bus,Kelly needs 35 minutes to walk home from a friend's house,30 minutes for dinner,and 20 minu

tes to drive to the class. To make class on time,what is the latest time she should leave her friend's house? What is the equation for this problem?
Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0
20+35+30= 1 hr&25 min so she should leave at 5:20
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Write an equation in point-slope form for the line that passes through the point with the given slope.
Vlad [161]
<h2>Answer:</h2>

I hope that it will be help full to u

<h2>Step-by-step explanation:</h2>

As we know point slope form ,

(Y- Y1) = m (X- X1)

As given data ,  

m =4/3

(X1,Y1) =  (-2, 11)

X1=-2 , Y1=  11

putt in the above equation these values, we get

Y-11 = (4/3) ( X-(-2))

Y-11 = (4/3)X +8/3

Y= (4/3)X +8/3+11

<h2><u>Y= (4/3)X + 41/3 Ans</u></h2>
7 0
3 years ago
Given that the line y=c-2x is tangent to the curve y^2=kx where c and k are non-zero constants,express k in terms of c
Viktor [21]

Answer:

k = -8c.

Step-by-step explanation:

y^2 = kx

Find the slope of the tangent by differentiating:

y' 2y = k

y' = k / 2y = the slope of the tangent.

The given equation of the tangent is y = -2x + c so the slope = -2.

Therefore  k/2y =  -2  so k = -4y and y = -k/4

y^2 = kx so k^2/16 = kx giving x = k/16.

Substituting for x and y in y = -2x + c:

-k/4 = -2 k/16 + c

-k/4 = -k/8  + c

c = -k/4 + k/8 = -k/8.

So -k = 8c

k = -8c.

3 0
4 years ago
What is the perimeter of a square with a side length 6x - 5
jolli1 [7]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{24x - 20}}}}}

Step-by-step explanation:

Given,

Length ( L ) = 6x - 5

Perimeter of a square ( P ) = ?

<u>Finding </u><u>the </u><u>perimeter </u><u>of </u><u>a </u><u>square </u><u>having </u><u>length </u><u>of </u><u>6</u><u>x</u><u>-</u><u> </u><u>5</u>

\boxed{ \bold{ \boxed{ \sf perimeter \: of \: a \: square \:  = 4l}}} ( where l is the side of the square )

plug the value of length

⇒\sf{4(6x - 5)}

Distribute 4 through the parentheses

⇒\sf{4 \times 6x - 4 \times 5}

⇒\sf{24x - 20}

Hope I helped!

Best regards!!

4 0
3 years ago
Ann's watch runs 2 minutes per hour too slow. Beth's watch runs 1 minute per hour too fast. For example, if both watches were co
Elenna [48]

Answer:

8 am Monday

Step-by-step explanation:

The difference between the two watches is  2+1= 3 minutes.

It would take 60/3 = 20 hours to have a difference of 60 minutes.

From noon Sunday it would be more 20 hours the earliest time there would be a difference of one hour between the two watches' time.

12 noon + 20 hours=  8 am Monday

7 0
3 years ago
Can someone please help me:)
Zarrin [17]

Answer:

I don't know what you are saying and please zoom it I can't understand.

6 0
3 years ago
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