A). 12 ÷ $7.20 = about $1.67 per muffin
b). 8 ÷ $4.40 = about $1.81 per muffin
c). 6 ÷ $4.50 = about $1.33 per muffin
type C costs the least per muffin
Answer:
n = 64
Step-by-step explanation:
We can solve using cross products
10/15 = n/96
10*96 = 15*n
960 = 15n
Divide each side by 15
960/15 =15n/15
64 = n
Answer: 0.02
Step-by-step explanation:
OpenStudy (judygreeneyes):
Hi - If you are working on this kind of problem, you probably know the formula for the probability of a union of two events. Let's call working part time Event A, and let's call working 5 days a week Event B. Let's look at the information we are given. We are told that 14 people work part time, so that is P(A) = 14/100 - 0.14 . We are told that 80 employees work 5 days a week, so P(B) = 80/100 = .80 . We are given the union (there are 92 employees who work either one or the other), which is the union, P(A U B) = 92/100 = .92 .. The question is asking for the probability of someone working both part time and fll time, which is the intersection of events A and B, or P(A and B). If you recall the formula for the probability of the union, it is
P(A U B) = P(A) +P(B) - P(A and B).
The problem has given us each of these pieces except the intersection, so we can solve for it,
If you plug in P(A U B) = 0.92 and P(A) = 0.14, and P(B) = 0.80, you can solve for P(A and B), which will give you the answer.
I hope this helps you.
Credit: https://questioncove.com/updates/5734d282e4b06d54e1496ac8
Answer:
y= -6+2/3x
Step-by-step explanation:
2x-3y=18
Minus the 2x from both sides
-3y=18-2x
Then divide both sides by -1
-3y÷-1=18÷-1 -2x÷-1
Lastly divide both sides by 3
3y÷3= -18÷3+2x÷3
3 boxes of computer diskettes at $8.99 per box = (3 * 8.99 = 26.97 )
2 packages of pens at $ 2.50 per package = (2 * 2.50 = 5.00 )
6 boxes of paper at $ 22.95 per box = (6 * 22.95 = 137.70)
1 printer ribbon at $25 each. = (1 * 25 = 25)
Add up (26.97+5.00+137.70+25 ) and the answer is = 194.67
