Wich is the unknown number? which property did u use?
2 answers:
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Answer:
(a) The cumulative frequency curve for the data is attached below.
(b) (i) The inter-quartile range is 10.08.
(b) (ii) The 70th percentile class scores is 0.
(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.
Step-by-step explanation:
(a)
To make a cumulative frequency curve for the data first convert the class interval into continuous.
The cumulative frequencies are computed by summing the previous frequencies.
The cumulative frequency curve for the data is attached below.
(b)
(i)
The inter-quartile range is the difference between the third and the first quartile.
Compute the values of Q₁ and Q₃ as follows:
Q₁ is at the position:
The class interval is: 34.5 - 39.5.
The formula of first quartile is:
Here,
l = lower limit of the class consisting value 25 = 34.5
(CF) = cumulative frequency of the previous class = 24
f = frequency of the class interval = 20
h = width = 39.5 - 34.5 = 5
Then the value of first quartile is:
The value of first quartile is 34.75.
Q₃ is at the position:
The class interval is: 44.5 - 49.5.
The formula of third quartile is:
Here,
l = lower limit of the class consisting value 75 = 44.5
(CF) = cumulative frequency of the previous class = 74
f = frequency of the class interval = 15
h = width = 49.5 - 44.5 = 5
Then the value of third quartile is:
The value of third quartile is 44.83.
Then the inter-quartile range is:
Thus, the inter-quartile range is 10.08.
(ii)
The maximum upper limit of the class intervals is 69.5.
That is the maximum percentile class score is 69.5th percentile.
So, the 70th percentile class scores is 0.
(iii)
Compute the probability that a student scored at most 50 on the examination as follows:
Thus, the probability that a student scored at most 50 on the examination is 0.89.
Okay, first, given the equation, we need to find out what the radius of the circle is. Let us state the general equation of a circle:
Where
is the centre of the circle. In this case, we don't need to know the centre. Just the radius.
Let us start by converting the equation into standard for, which I typed above. Divide both sides by 81.
Great! We now know the radius of the circle. It is
because it is the bottom fraction. Now we know that the radius is 9.
So now lets input this into the area of circle formula:
Now we insert our radius.
You can convert that into a decimal if you wish.
Hope this helped!
~Cam943, Moderator
Where
Let us start by converting the equation into standard for, which I typed above. Divide both sides by 81.
Great! We now know the radius of the circle. It is
So now lets input this into the area of circle formula:
Now we insert our radius.
You can convert that into a decimal if you wish.
Hope this helped!
~Cam943, Moderator