You cannot add row 2 to column 3 because they have different dimensions. You can do any of the other operations, but the only one that makes any sort of sense is ...
Multiply row 2 by -1 and add it to row 3
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It makes no sense to multiply a row by zero. That makes the entire row zero and makes the matrix useless for finding any sort of solution.
You can switch columns, but that doesn't get you any closer to a solution here.
If I were trying to find a solution, I might
switch rows 1 and 2
multiply the new row 1 by -3 and add it to the new row 2
multiply the new row 1 by 2 and add it to row 3
This sequence of operations will make the first column [1 0 0], reducing the problem to 2×2 from 3×3.
Answer:
The Solution Set
Step-by-step explanation:
Despite missing some context, the output we could get as result of an expression/equation it is what we call a Solution set. A set which makes the initial statement of equation/expression true, therefore valid.
Therefore, the elements of the Solution set, 3 and 4 when plugged into the equation make the statement of the quadratic equation true.
<h2>Just switch x and y</h2>
Answer:
Option A
Step-by-step explanation:
A = 3 +3 +3+3 = 12
B = 3⁴ = 81
C = 3² × 3² = 9 × 9 = 81
D = 3× 3 × 3 × 3 = 81
Answer:
8
Step-by-step explanation:
Volume of a cone formula: V = 
where,
h is the height <u>9 in (assuming)</u>
r is the radius <u>want</u>
v is the volume <u> 602.88 cubic inches</u>
is <u>a = 3.14 </u>
Plug in everything:
