From the given figure ,
RECA is a quadrilateral
RC divides it into two parts
From the triangles , ∆REC and ∆RAC
RE = RA (Given)
angle CRE = angle CRA (Given)
RC = RC (Common side)
Therefore, ∆REC is Congruent to ∆RAC
∆REC =~ ∆RAC by SAS Property
⇛CE = CA (Congruent parts in a congruent triangles)
Hence , Proved
<em>Additional</em><em> comment</em><em>:</em><em>-</em>
SAS property:-
"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)
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Consider the proof. Given: Segment AB is parallel to line DE. Prove: AD/DC = BE/EC What is the missing statement in Step 5? A.) AC = BC B.) AC/DC = BC/EC C.) AD...
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It’s E :) it’s up 20 characters
I got 9.8 but if you want to round it you get 10 because you add 106 and 9 to get 115 and then add 3 and get 118 and then divide 12b and 118 and get 9.8
Answer:
f(x) = 2x+1
Step-by-step explanation:
Equation in slope intercept form y = mx + b where m = slope b = y-intercept
To find slope ,
m = (y2-y1)/(x2 - x1)
m = (3 - 1) / (1 - 0)
m = 32/1
m = 2
y-intercept b = 1
In this case y = 2x + 1 or f(x) = 2x+1