Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
D) 286.7 because the number is rounded to your nearest tenth
Answer:
multiply the length value by 1760
2.4*1760 is 4224
Step-by-step explanation:
Answer:
divide 4. from 4 n 3. 3 divided by 4 answer us the answer fir x and then you times that answer to 4 and that is the answer for y
For this case, the first thing to do is to observe that the figure is symmetrical with respect to the FH axis.
Therefore, the following lengths are the same:
So, by equalizing both sides we have:
From here, we clear the value of m.
We have then:
Answer:
The value of m is given by:
