=−2x^2 +8 +3 write in vertex form
1 answer:
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Answer: The minimum value of C is 46.
Step-by-step explanation:
Since, Here, We have to find out Min C = 7x+8y
Given the constraints are -------(1)
------------- (2)
,
-------- (3)
Since, For equation 1) x-intercept, (4, 0) and y-intercept (0,8)
And, ⇒
( false)
Therefore the area of line 1) does not contain the origin.
For equation 2) x-intercept, (6, 0) and y-intercept (0,6)
And, ⇒
( false)
Therefore the area of line 2) does not contain the origin.
Thus after plotting the constraints 1) 2) and 3) we get Open Shaded feasible region AEB ( Shown in below graph)
At A≡(0,8) , C= 64
At E≡(2,4), C= 46
At B≡(6,0), C= 42
Thus at B, C is minimum, And its minimum value = 42
Answer:
The lines representing these equations intercept at the point (-4,2) on the plane.
Step-by-step explanation:
When we want to find were both lines intercept, we are trying to find a pair of values (x,y) that belongs to both equations, which means that it satisfies both equations at the same time.
Therefore, we can use the second equation that gives us the value of y in terms of x, to substitute for y in the first equation. Then we end up with an equation with a unique unknown, for which we can solve:
Next we use this value we obtained for x (-4) in the same equation we use for substitution in order to find which y value corresponds to this:
Then we have the pair (x,y) that satisfies both equations (-4,2), which is therefore the point on the plane where both lines intercept.