Im thinking 226.08
v=1/3pie r^2 h
v=1/3Pie (6) ^2 (6)
v=1/3 pie (36) (6)
v=1/3 pie (216)
v=72 pie
72 x 3.14=226.08
Answer:
11 + n
Step-by-step explanation:
sum means addition, so u need a + sign
n is usually the variable used for 'a number'
so 11 and (+) a number (n) = 11+ n
hope this helps!
Answer:
123added 23
Step-by-step explanation:
Answer: 490 grams of the first alloy should be used.
30 grams of the second alloy should be used.
Step-by-step explanation:
Let x represent the weight of the first alloy in grams that should be used.
Let y represent the weight of the second alloy in grams that should be used.
A chemist has two alloys, one of which is 15% gold and 20% lead. This means that the amount of gold and lead in the first alloy is
0.15x and 0.2x
The second alloy contains 30% gold and 50% lead. This means that the amount of gold and lead in the second alloy is
0.3y and 0.5y
If the alloy to be made contains 82.5 g of gold, it means that
0.15x + 0.3y = 82.5 - - - - - - - - - - - -1
The second alloy would also contain 113 g of lead. This means that
0.2x + 0.5y = 113 - - - - - - - - - - - - -2
Multiplying equation 1 by 0.2 and equation 2 by 0.15, it becomes
0.03x + 0.06y = 16.5
0.03x + 0.075y = 16.95
Subtracting, it becomes
- 0.015y = - 0.45
y = - 0.45/- 0.015
y = 30
Substituting y = 30 into equation 1, it becomes
0.15x + 0.3 × 30 = 82.5
0.15x + 9 = 82.5
0.15x = 82.5 - 9 = 73.5
x = 73.5/0.15
x = 490
The first thing we must do for this case is to define a variable.
We have then:
x: weight of each pallet with cement
We then have the following equation:
16x = 4856
Clearing x we have:
x = (4856) / (16)
x = 303.5 punds
Answer:
each pallet with cement weigh:
x = 303.5 punds
