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Keith_Richards [23]
3 years ago
15

How can you determine the type of the triangle based on the lengths of the sides in a triangle?

Mathematics
1 answer:
Mama L [17]3 years ago
6 0

Answer:

You can determine the type of triangle using the following facts related to the converse of the pythag theorem

if a^2 + b^2 > c^2, then it is an obtuse triangle

if a^2+b^2<c^2, then it is an acute triangle

finally, if a^2+b^2=c^2, then it is a right triangle

<u><em>NOTE THAT C ALWAYS EQUALS THE LONGEST LENGTH OF THE TRIANGLE!!!</em></u>

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Evaluate the following expression when x = -1, y = 2, z = -3, and<br> w = 4.<br> x² - y²
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Answer:

-3

Step-by-step explanation:

-1*-1=1

2*2=4

1-4

=-3

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If p varies directly with q, and p = 10 when q = 5, what is the value of p when q = 20
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6 1/2 how many inches ​
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78 inches

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Classify the polygon by its number of sides. Does the polygon appear to be regular or not regular?
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3 years ago
The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
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