Oh, I remember this one. Here's this if you need it, if it doesn't help then let me know.
Step 1:
In a sample of 380 randomly selected reservations, 19 were no-shows.
Step 2:
Proportion of no shows p<0.06.
Step 3:
Test Value
z(19/380)=0.05
Step 4:
Test statistics
a) 0.05-1.124=-1.074
b) 0.05-(-1.943) = 0.05+1.943=1.993
c)0.05-(-0.821)=0.05+0.821=0.871
d)0.05 - 0.222 = - 0.172
e)0.05 -(-1.571) = 0.05+1.571 = 1.621
The above data clearly mentions the test statistics associated with the given samples.
5/6= c/9
Cross mutiple. 5* 9= 45 . c*6
45= 6c
divide by 6 for 45 and 6c
45/6= 6c/6
45/6= c
Reduce 45/6. Divide by 3
45/3, 6/3
15/2= c
Answer: c= 15/2 or in decimal form , c= 7.5
Answer:
B. (x-3)^2
Step-by-step explanation:
x^2-6x+9 = (x-3)^2
(a-b)^2=a^2-2ab+b^2
(a+b)^2=a^2+2ab+b ^2
