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Leona [35]
3 years ago
10

Use visual clues to decide which plot has the highest

Mathematics
2 answers:
kodGreya [7K]3 years ago
8 0

Answer:

aabb

Step-by-step explanation:

lakkis [162]3 years ago
6 0

Answer: highest mean: plot 1. Highest median: plot 1. Highest range: plot 2. Highest interquartile ranges: plot 2.

Step-by-step explanation:

i got it right lol

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6=4y+2 what is the answer
blagie [28]
Answer: 1 = y
All you have to do is carry the 2 over and subtract it from 6 so then you just have 4=4y which will turn into 1=y
6 0
3 years ago
Factor 4x12−25y6<br><br> .<br><br> Enter your answer in the box.
Rainbow [258]
I got 256 as the answer
6 0
3 years ago
I NEED HELP ASAP!!!! PLEASE HELP!!!
IRISSAK [1]

Answer:

y= 2x-3  m=2 b= -3

Step-by-step explanation:

we distribute 2(x-2)

y-1 = 2(x-2)

y-1 = 2x-4

then add one to both sides

y-1= 2x -4

 +1       +1

since it is negative four and you are adding one it would be -3

y= 2x -3  that is your slope intercept form.

y= mx +b  so m=2 and b= -3

6 0
3 years ago
Please someone help me...​
laiz [17]

Step-by-step explanation:

First factor out the negative sign from the expression and reorder the terms

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )}  -  \frac{1}{ \cot(6A)  -  \cot(2A) }

<u>Using trigonometric </u><u>identities</u>

That's

<h3>\cot(x)  =  \frac{1}{ \tan(x) }</h3>

<u>Rewrite the expression</u>

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )} -    \frac{1}{ \frac{1}{ \tan(6A) } }  -  \frac{1}{ \frac{1}{ \tan(2A) } }

We have

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{1}{ \frac{ \tan(2A) -  \tan(6A)  }{ \tan(6A) \tan(2A)  } }</h3>

<u>Rewrite the second fraction</u>

That's

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{ \tan(6A)  \tan(2A) }{ \tan(2A) -  \tan(6A)  }</h3>

Since they have the same denominator we can write the fraction as

-  \frac{1 +  \tan(6A) \tan(2A)  }{ \tan(2A) -  \tan(6A)  }

Using the identity

<h3>\frac{x}{y}  =  \frac{1}{ \frac{y}{x} }</h3>

<u>Rewrite the expression</u>

We have

<h3>-  \frac{1}{ \frac{ \tan(2A)  -  \tan(6A) }{1 +  \tan(6A) \tan(2A)  } }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{ \tan(x) -  \tan(y)  }{1 +  \tan(x)  \tan(y) }  =  \tan(x - y)</h3>

<u>Rewrite the expression</u>

That's

<h3>- \frac{1}{ \tan(2A -6A) }</h3>

Which is

<h3>-  \frac{1}{ \tan( - 4A) }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{1}{ \tan(x) }  =  \cot(x)</h3>

Rewrite the expression

That's

<h3>-  \cot( - 4A)</h3>

<u>Simplify the expression using symmetry of trigonometric functions</u>

That's

<h3>- ( -  \cot(4A) )</h3>

<u>Remove the parenthesis </u>

We have the final answer as

<h2>\cot(4A)</h2>

As proven

Hope this helps you

6 0
3 years ago
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Please Help On These 3 Questions . I will reward brainliest!
Luden [163]
In my opinion, id say A and B
4 0
3 years ago
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