Answer:
Why do we have to get homework???sorry for not answering ur equations I don't know em as yet
Answer:
Step-by-step explanation:
If a point (x, y) is rotated 90° counterclockwise about the origin, rule for the rotation will be,
(x, y) → (-y, x)
Therefore, coordinates of the image point after the rotation will be (-y, x).
Following this rule,
Image points of the quadrilateral will be,
A(3, 3) → A'(-3, 3)
R(5, 7) → R'(-7, 5)
M(7, 5) → M'(-5, 7)
Y(5, 1) → Y'(-1, 5)
By graphing the image points we can get the graph of the image quadrilateral A'R'M'Y'.
15 + 38 = 53
180 - 54 = 127
Answer:
Photo.
Step-by-step explanation:
A: The graph of the system is all points in the graph that suit 4x-2<y</=-5/2x-2
B: The point (-2,-2) is not included in the solution area. While it suits the second equation, it doesn't suit the first, ruling it out as a possible solution. If you plug in -2 as both y and x in the equation 4x-2>y, you'll get -8>-2, which is false. So, it is not a solution.
The rule for this one is called the difference of squares
A^2 - b ^2 = (a+b)(a-b)
Using this rule
N^2 - 62 = (n+ sqrt(62)) (n - sqrt(62))
The solution for this one is to make the statement = 0
0 = (n+ sqrt(62)) (n - sqrt(62))
N can either be +- sqrt(62)