1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Maslowich
3 years ago
15

In a city, the distance between the library and the police station is 3 miles less than twice the distance between the police

Mathematics
2 answers:
Tresset [83]3 years ago
4 0

Answer:

4 :)

Step-by-step explanation:

Lyrx [107]3 years ago
3 0

Answer:

Option 3 - 4 miles

Step-by-step explanation:

Given : In a city, the distance between the library and the police station is 3 miles less than twice the distance between the police  station and the fire station. The distance between the library and the police station is 5 miles.

To find : How far apart are the police  station and the fire station?

Solution :

Let the distance between police station and fire station be 'x'.

The distance between the library and the police station is 3 miles less than twice the distance between the police  station and the fire station.

i.e. 2x-3

The distance between the library and the police station is 5 miles.

i.e. 2x-3=5

2x=5+3

2x=8

x=4

Therefore, The police and fire stations is 4 miles apart.

So, Option 3 is correct.

You might be interested in
Someone help and plz make sure it’s right plz! :)
kvv77 [185]

Answer:

-21/4

Step-by-step explanation:

slope = y2-y1/ x2-x1

-18 - 3 / 17-13 = -21/4

4 0
3 years ago
PLEASE ANSWER ALL OF THESE FOR 97 POINTS AND YOU ARE THE GOAT
harkovskaia [24]

Answer: It dosn't show anything for me. did you post it?

6 0
3 years ago
Read 2 more answers
Pls I help I need answers and work shown
WITCHER [35]

0.30 as a fraction is 30/100 = 3/10

0.30 as a percent = 0.30 * 100 = 30%

 answer is D. 3/10 and 30%

4 0
3 years ago
Read 2 more answers
Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least
Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

<u><em>1) The probability of having a face card in the first turn</em></u>

In this case, the chances are 12 in 52:

P_1=P(face\, card)=12/52=0.231

<u><em>2) The probability of having a face card in the second turn, having a non-face card in the first turn.</em></u>

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181

<u><em>3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.</em></u>

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141

<u><em>4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.</em></u>

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109

With these four probabilities we can calculate the probability of losing this bet:

P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

P=P_1+P_2+P_3=0.231+0.181+0.141=0.553

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0
3 years ago
PLZ HELP ME WITH THIS IT DUE TODAY.I GIVE YOU BRAINLEST JUST PLEASE HELP!!!! THANK YOU!
Fiesta28 [93]
I’m not sure about number 1 but the answer for number 2 is

-4 1/2, -4.2, -4, ,0, 4
5 0
3 years ago
Other questions:
  • What number can you multiply by π to get a rational number?
    6·2 answers
  • 2 + (3 – 2 x 2) *1<br> What’s the answer on this <br> Problem
    12·1 answer
  • There are 38 chocolates in a box, all identically shaped. there are 15 filled with nuts, 10 with caramel, and 13 are solid choco
    13·2 answers
  • On Sunday, Sheldon bought 4 1/2 kg of plant food. He used 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plant
    15·1 answer
  • Convert the following into millilitres a)13 litres​
    11·2 answers
  • What is the least common multiple of 420 and 1848?
    7·1 answer
  • Chad and his son go into a grocery store and need to buy bananas. Each banana costs $0.90 and Chad has a total of $11 to spend.
    5·1 answer
  • Offering 50 points really need help on homework
    14·1 answer
  • Plzzz help me plz Show how to find the x-intercepts of this parabola using factoring and the Zero Product Property. Select the a
    13·1 answer
  • he seven problems, which were announced in 2000, are the Riemann hypothesis, P versus NP problem, Birch and Swinnerton-Dyer conj
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!