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anzhelika [568]
3 years ago
6

Cindy went to Maggie Moo's for an ice cream cone after school. The ice cream cone had a radius of 3 inch, a

Mathematics
1 answer:
anzhelika [568]3 years ago
7 0

Answer: The cone can hold 18.84 cubic inches of ice cream.

Step-by-step explanation:

Hi, to answer this question we have to find the volume of a cone, using only the height (h) and the radius(r) values.

Volume of a cone (V) = 1/3 π r² h

Replacing with the values given:

V = 1/3 (3.14) (3)² 2  

Solving:

V = 1/3 (3.14) (9) 2

V = 18.84 cubic inches

In conclusion, the cone can hold 18.84 cubic inches of ice cream.

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miss Akunina [59]

Answer:

x: length

y: wide

x = 3y and x*y =192

=> 3y^2 = 192

=> y = 8 => x =3x8 = 24

=> Perimeter = (x+y)*2 = (8+24)*2 = 64

5 0
3 years ago
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En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand
Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} (1)

Donde:

F_{1} - Fuerza experimentada por el elefante, medida en newtons.

F_{2} - Fuerza aplicada sobre el plato pequeño, medida en newtons.

A_{1} - Área del plato grande, medida en metros cuadrados.

A_{2} - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g (2)

Donde:

D_{1} - Diámetro del plato grande, medido en centímetros.

D_{2} - Diámetro del plato pequeño, medido en centímetros.

m - Masa del elefante, medida en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que D_{1} = 0.75\,m, D_{2} = 0.13\,m, m = 2900\,kg y g = 9.807\,\frac{m}{s^{2}}, entonces la fuerza a aplicar al émbolo pequeño es:

F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F_{2} = 854.473\,N

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

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What's the simplified form of this expression? 3-[-2/3 x (7 +2) =11]
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Answer:

x = 4/3

Step-by-step explanation:

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Step-by-step explanation:

\angle AOB and \angle BOC are linear pair angles.

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If 300 words or typed in 6 minutes how many words will be typed in 17 minutes
Ierofanga [76]

Answer:

850 words can be typed in 17 minutes

Step-by-step explanation:

Divide 300 by 6 and multiply it by 17 and that is your answer, 850.

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