Answer:
x=2
Step-by-step explanation:
Answer:
C) 14
Step-by-step explanation:
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, add 6 to both sides:
3x - 6 (+6) = 36 (+6)
3x = 36 + 6
3x = 42
Next, divide 3 from both sides:
(3x)/3 = (42)/3
x = 42/3
x = 14
c) 14 is your answer.
~
Answer:
The points that are not coplaner are
w &q
w&R
w&t
w&s
Y=36 is the y-intercept simply substitute 0 as x
If you use this equation then you say that the ground is h=0 and solve as a quadratic.
The quadratic formula is (-b±<span>√(b^2-4ac))/2a when an equation is in the form ax^2 + bx + c
So the equation you have been given would be -16t^2-15t-151 = 0
This equation has no real roots which leads me to believe it is incorrect.
This is probably where your difficulty is coming from, it's a mistake.
The equation is formed from S=ut+(1/2)at^2+(So) where (So) is the initial height and S is the height that you want to find.
In this case you want S = 0.
If the initial height is +151 and the initial velocity and acceleration are downwards (negative) and the initial velocity (u) is -15 and the initial acceleration is -32 then you get the equation S=-15t-16t^2+151
Solving this using the quadratic formula gives you t = 2.64 or t = -3.58
Obviously -3.58s can't be the answer so you're left with 2.64 seconds.
Hope this makes sense.
</span><span>
</span>
