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Solnce55 [7]
3 years ago
6

Someone pls help me answer this????? THE POINTS ARE (3,-4) And (3,5)

Mathematics
1 answer:
irina [24]3 years ago
3 0
The circle goes thru the given points <span>(3,-4) And (3,5).  Since the x-coordinate does not change, the diameter lies right on the vertical line x=3.  Since the vertical distance between these points is 5-(-4), or 9, the radius is 9/2.

The standard eq'n of a circle is (x-h)^2 + (y-k)^2 = r^2

Let's subst. what we know:  we get   (x-3)^2 + (y-1/2)^2 = (9/2)^2.  Note that y = 1/2 is halfway between y=-4 and y=5.</span>
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The line passes through (9,8) and is perpendicular to x-2y=-16
pickupchik [31]

The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26

Step-by-step explanation:

Given

x-2y=-16\\Adding\ 2y\ on\ both\ sides\\x=2y-16\\Adding\ 16\ on\ both\ sides\\x+16=2y-16+16\\x+16=2y\\2y=x+16\\Dividing\ both\ sides\ by\ 2\\\frac{2y}{2}=\frac{x+16}{2}\\y=\frac{x}{2}+\frac{16}{2}\\y=\frac{1}{2}x+8\\

The equation is in slope-intercept form,  the coefficient of x will be the slope of given line. The slope is: 1/2

As the product of slopes of two perpendicular lines is -1.

\frac{1}{2}*m=-1\\m=-1*\frac{2}{1}\\m=-2

Slope intercept form is:

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Putting the value of slope

y=-2x+b

To find the value of b, putting (9,8) in the equation

8=-2(9)+b\\8=-18+b\\b=8+18\\b=26

Putting the values of b and m

y=-2x+26

Hence,

The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26

Keywords: Equation of line, Slope-intercept form

Learn more about equation of line at:

  • brainly.com/question/1993757
  • brainly.com/question/2048256

#LearnwithBrainly

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there are 28 quarters and 13 nickels

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