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adelina 88 [10]
3 years ago
12

rectangles a and b have the same perimeter but are different shapes. rectangle a is 5 inches long and 3 inches wide. rectangle b

is 6 inches longer than it is wide. what are the length and width of rectangle b?
Mathematics
1 answer:
torisob [31]3 years ago
6 0
The length is 7 and the width is 1

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A bag contains 100 marbles which are red, green, and blue. Suppose a student randomly selects a marble without looking, records
ra1l [238]

Answer:

35 red marbles

Step-by-step explanation:

So we can put the different color marbles in a ratio. So 7:2:11. If we add all of those up we get 20. We do 100/20 to get 5. Each number in the ratio is equivalent to 5 marbles. Then we do 7*5 to get 35. We can check our work by doing, (7*5) + (2*5) + (11*5) = 100. And it does equal 100 so the answer is correct.

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You rent an apartment that costs $900 per month during the first year, but the rent is
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Answer:1493.1

Step-by-step explanation:

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2 years ago
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At what point do the graphs of 9x - 2y = 30 and x + 2y = 10 intersect
strojnjashka [21]

Answer:

(4,3)

Step-by-step explanation:

4 0
3 years ago
Please tell me answer not by directly step by step please don't write answer only please please please
irinina [24]

Step-by-step explanation:

Given,

y=2x=,z=3x,r=4x

Now,

x+y+z+r=360°(complete turn)

x+2x+3x+4x=360°(given)

10x=360°

x=360°/10

x=36°

Hence,

x=36°

y=2x=2×36°=72°

z=3x=3×36°=108°

r=4x=4×36°=144°

7 0
3 years ago
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B A pair of fair dice is rolled, If the sum of the spots is 7, determine the probability that one di showed a 2.
finlep [7]

Answer:

\text{Probability}=\frac{1}{3}

Step-by-step explanation:

Given : A pair of fair dice is rolled, If the sum of the spots is 7.

To find : Determine the probability that one die showed a 2 ?

Solution :

A pair of fair dice is rolled the outcomes are,

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

The sum of the spots is 7 i.e. (4,3),(2,5),(5,2),(3,4),(1,6),(6,1).

Total possibility = 6

Favorable outcome is that one die showed a 2 i.e. (2,5),(5,2)= 2

The probability that one die showed a 2 is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{2}{6}

\text{Probability}=\frac{1}{3}

8 0
3 years ago
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