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choli [55]
3 years ago
8

Help pls what is the sum of the rational expressions below

Mathematics
1 answer:
CaHeK987 [17]3 years ago
6 0

Answer:

the answer is A

Step-by-step explanation:

hope its right solved it myself but i know u need it fast

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Priya says these polygons are similar because their side lengths are the same. Clare says "these explain polygons are not simila
taurus [48]

Answer:

Clare is correct

Step-by-step explanation:

For two shapes to be congruent, the shape and size have to be the same. In other words they ate have to equal length in size and also equal angles(same shape hence equal angles). Therefore Clare is correct since only have equal length in sides does not qualify the polygon to be congruent or similar like Priya claims

3 0
2 years ago
Which expression shows 18 + 15 written as a product of two factors?
____ [38]
1st one is ur answer
6 0
3 years ago
Read 2 more answers
The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room
Alexandra [31]

Answer:

\bar x = 260.1615

\sigma = 70.69

The confidence interval of standard deviation is: 53.76 to 103.25

Step-by-step explanation:

Given

n =20

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}

\bar x = \frac{5203.23}{20}

\bar x = 260.1615

\bar x = 260.16

Solving (b): The standard deviation

This is calculated as:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}

\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}\sigma = \sqrt{\frac{94938.80}{19}}

\sigma = \sqrt{4996.78}

\sigma = 70.69 --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

c =0.95

So:

\alpha = 1 -c

\alpha = 1 -0.95

\alpha = 0.05

Calculate the degree of freedom (df)

df = n -1

df = 20 -1

df = 19

Determine the critical value at row df = 19 and columns \frac{\alpha}{2} and 1 -\frac{\alpha}{2}

So, we have:

X^2_{0.025} = 32.852 ---- at \frac{\alpha}{2}

X^2_{0.975} = 8.907 --- at 1 -\frac{\alpha}{2}

So, the confidence interval of the standard deviation is:

\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} } to \sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }

70.69 * \sqrt{\frac{20 - 1}{32.852} to 70.69 * \sqrt{\frac{20 - 1}{8.907}

70.69 * \sqrt{\frac{19}{32.852} to 70.69 * \sqrt{\frac{19}{8.907}

53.76 to 103.25

8 0
2 years ago
What is the total amount of 2/5+5/3+9/3 and the lowest common denominator?
gregori [183]

The lowest common denominator is lcm(5, 3), which is 15.

The sum of 2/5 + 5/3 + 9/3 is 6/15 + 25/15 + 45/15, which is 76/15 or 5\frac{1}{15}.

4 0
3 years ago
A student has gotten the following grades on his tests. What is the minimum grade he must get on the last test in order to have
arsen [322]

The lowest grade that student could get is a 91 or higher

7 0
3 years ago
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