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3 years ago

Some people took part in a game. The frequency shows information about their scores.

Mathematics

1 answer:

Wittaler [7]3 years ago

3 0

80
117
169
180
448
817
=
1811 / 91

19.901 and that rounded to 2 decimal places is 19.9

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What transformation occurs to f(x) in the function f(x)-7

BlackZzzverrR [31]

Answer:

left 7

Step-by-step explanation:

5 0

3 years ago

2 numbers are in the ratio 1:2 if the first number is decreased by 5 and second number is increased by 4 their ratio becomes 5:4

Anna35 [415]

Answer:

-20/3 & -40/3

Step-by-step explanation:

Let’s say that the 1st number is X and the 2nd number is Y.

Given that x:y = 1:2 => x/y = 1/2 => 2x = y

and a-5/y+4 = 5/4 (The first number is decreased by 5 and the second number is increased by 4.)

=> 4(x - 5) = 5 (y + 4)

=> 4x - 20 = 5y + 20

=> 4x - 5y = 40

As, 2x = y , 4x = 2y

=> 2y - 5y = 40

=> -3y = 40

=> y = -40/3 ; x = y/2 = -20/3

This might be confusing but I hope this helps :)

7 0

3 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago

Please answer this correctly I have to finish the sums today as soon as possible

padilas [110]

Answer:

All of them

Step-by-step explanation:

ツ

3 0

3 years ago

Joe drank 4 liters of water on Monday an 4 deciliters of water on Tuesday how much more water did he drink on Monday than on Tue

oksian1 [2.3K]

10 times the amount, or 3.6 liters more.

8 0

3 years ago