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Delicious77 [7]
3 years ago
9

How to find the zero of (x - 2)^3= 0

Mathematics
1 answer:
Arturiano [62]3 years ago
8 0
By solving the factors thats working fronwards or you can work backward from zero
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The graph of a linear relationship is shown below. Does this graph show a proportional relationship?
Leona [35]
Yes it does because the line is straight.
3 0
3 years ago
I NEED THE ANSWER ASAP!!!
iren2701 [21]

Answer:

b i think

Step-by-step explanation:

6 0
3 years ago
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Given: AC and AE are common external tangents of G and D. BC= 123 GB=20 and AG=101. What is the measure of AC?​
Solnce55 [7]

Answer:

The length of AC is 222 units.

Step-by-step explanation:

Given AC and AE are common external tangents of G and D.

BC= 123 ,  GB=20 and AG=101.

We have to find the measure of AC.

As, a straight line joined from the center i.e radius is perpendicular to tangent drawn. Therefore,

In ΔABG, by Pythagoras theorem

AG^2=AB^2+BG^2

⇒ 101^2=AB^2+20^2

⇒ AB^2=10201-400=9801

⇒ AB=99 units.

Hence, AC=AB+BC=99+123=222 units.

The length of AC is 222 units.

8 0
3 years ago
Find the greatest common factor of 15x^2y^3 and -18x^3yz <br> The Answer has to be like _x_y_
Daniel [21]

Answer:

The greatest common factor of this would be 3x^2y

Step-by-step explanation:

In order to find this, first find the greatest common factor of the coefficients. Since 3 goes in evenly to both 15 and -18, then we know that it is a common factor.

From there we need to find the number of x's. Since the first term only has 2 x's and the second has 3, we take the lowest number. (x^2)

And since the first term has 3 y's and the second has just 1, we take the lowest number (y).

8 0
3 years ago
Good evening! Can someone please answer this, ill give you brainliest and your earning 50 points. Would be very appreciated.
Tanzania [10]

Tyler concludes that 5x² will always have a larger output for the same value of x.

<u>Look at the graph below and the table given</u>

Take a random value: x = 0

  • When 5x², y = 0
  • When 2^x, y = 1

Here, 1 > 0, making 2^x > 5x²

Hence, 2^x is greater than 5x² at this point. making Tyler's point not applicable.

Disagree with Tyler's point.

7 0
2 years ago
Read 2 more answers
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