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Tomtit [17]
2 years ago
12

2)Write the equation 2x+2y=10 so that y is a function of x. Then find y when x is -2,0,2

Mathematics
1 answer:
il63 [147K]2 years ago
5 0
Rewrite 2x + 2y = 10 into slope-intercept form:

y(x)= mx + b

2x - 2x + 2y = -2x + 10

2y/2 = (-2x + 10)/2

y = -x + 5

y(x) = -x + 5

Next, we’ll find the value of y when x = -2, 0, 2:

y(-2) = -x + 5

y(-2) = -(-2) + 5
y(-2) = 2 + 5 = 7

Next, we’ll solve for y(0):

y(0) = -(0) + 5

y(0) = 0 + 5 = 5


Finally, we’ll find y(2):
y(2) = -(2) + 5

y(2) = -2 + 5

y(2) = 3
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it is up

Step-by-step explanation:

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Anddd Similar traingles for one more time.

Here,
RQ/RP = RS/RT = QS/PT = 1/2


Using the values of QS and PT will give,

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3 years ago
Find the sixth term of the sequence 1/2, -3/8, 9/32
sukhopar [10]

Answer:

The sixth term is -243/2048 ⇒ answer B

Step-by-step explanation:

* Lets explain the geometric sequence

- There is a constant ratio between each two consecutive numbers

- Ex:

# 5  ,  10  ,  20  ,  40  ,  80  ,  ………………………. (×2)

# 5000  ,  1000  ,  200  ,  40  ,  …………………………(÷5)  

* General term (nth term) of a Geometric sequence:

# U1 = a  ,  U2  = ar  ,  U3  = ar²  ,  U4 = ar³  ,  U5 = ar^4

# Un = ar^(n-1), where a is the first term , r is the constant ratio

  between each two consecutive terms  and n is the position of the

  number in the sequence

- Ex: U5 = ar^4  ,  U7 = ar^6  ,  U10 = ar^9  ,  U12 = ar^11

- Lets solve the problem

∵ The sequence is 1/2 , -3/8 , 9/32

- Lets find the constant ratio r

∵ The first term is a = 1/2

∵ The second term is U2 = ar

∵ The second term  U2 = -3/8

∴ ar = -3/8

∴ 1/2 r = -3/8 ⇒ multiply both sides by 2

∴ r = -3/4

- Lets find the sixth term

∵ a = 1/2 and r = -3/4

∵ n = 6

∴ U6 = ar^5

∴ U6 = 1/2 (-3/4)^5 = 1/2 × -243/1024 = -243/2048

* The sixth term is -243/2048

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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Therefore,

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m(ABC) = 218°

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