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3 years ago

13

Can 10-12 be solved Answer Fast!!!!!!

1 answer:

zzz [600]3 years ago

6 0

Answer:

10/------ 5x+2y=14

11/------ 1x+6y=2

12/ ----- 9x+6y=12

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Determine the coordinates of the vertices of the triangle to compute the area of the triangle using the distance formula (round

Karo-lina-s [1.5K]

Answer:

1. D. $50\text{ units}^2$

2. D. 45 units.

Step-by-step explanation:

We have been two graphs.

1. To find the area of our given triangle we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting coordinates of base line of our triangle we will get,

$\text{Base length of triangle}=\sqrt{(15-5)^2+(5-15)^2}$

$\text{Base length of triangle}=\sqrt{(10)^2+(-10)^2}$

$\text{Base length of triangle}=\sqrt{100+100}$

$\text{Base length of triangle}=\sqrt{200}$

$\text{Base length of triangle}=10\sqrt{2}$

Now let us find the height of triangle similarly.

$\text{Height of triangle}=\sqrt{(20-15)^2+(10-5)^2}$

$\text{Height of triangle}=\sqrt{(5)^2+(5)^2}$

$\text{Height of triangle}=\sqrt{25+25}$

$\text{Height of triangle}=\sqrt{50}$

$\text{Height of triangle}=5\sqrt{2}$

$\text{Area of triangle}=\frac{\text{Base*Height}}{2}$

$\text{Area of triangle}=\frac{10\sqrt{2}*5\sqrt{2}}{2}$

$\text{Area of triangle}=\frac{50*2}{2}$

$\text{Area of triangle}=50$

Therefore, area of our given triangle is 50 square units and option D is the correct choice.

2. Using distance formula we will find the length of large side of triangle as:

$\text{Large side of rectangle}=\sqrt{(14-1)^2+(21-8)^2}$

$\text{Large side of rectangle}=\sqrt{(13)^2+(13)^2}$

$\text{Large side of rectangle}=\sqrt{169+169}$

$\text{Large side of rectangle}=\sqrt{338}$

$\text{Large side of rectangle}=13\sqrt{2}$

$\text{Small side of rectangle}=\sqrt{(4-1)^2+(5-8)^2}$

$\text{Small side of rectangle}=\sqrt{(3)^2+(-3)^2}$

$\text{Small side of rectangle}=\sqrt{9+9}$

$\text{Small side of rectangle}=\sqrt{18}$

$\text{Small side of rectangle}=3\sqrt{2}$

$\text{Perimeter of rectangle}=2(\text{Length + Width)}$

$\text{Perimeter of rectangle}=2(13\sqrt{2}+3\sqrt{2}}$

$\text{Perimeter of rectangle}=2(16\sqrt{2}}$

$\text{Perimeter of rectangle}=32\sqrt{2}$

$\text{Perimeter of rectangle}=45.2548339959390416\approx 45$

Therefore, the perimeter of our given rectangle is 45 units and option D is the correct choice.

8 0

4 years ago

Read 2 more answers

This figure has a length of 10 cm, a width of 7 cm, and a height of 3 cm. What is its surface area?

pochemuha

About 210 centimeters

7 0

3 years ago

For each of the questions, find the value of x. If necessary, round your answer to the nearest tenth. The figure is not drawn to

Step2247 [10]

Answer:

1. D

2. D

3. C

Step-by-step explanation:

3 0

4 years ago

PLEASE HELP!!!!! IM VERY STRESSED

ololo11 [35]

X intercept (3/2 , 0)
Y intercept (0, -3)

7 0

3 years ago

Round 708,569 to the nearest ten thousand

Hoochie [10]

Answer:

710,000

Step-by-step explanation:

Make the number whose last four are <em>0</em><em>0</em><em>0</em><em>1</em> through <em>4</em><em>9</em><em>9</em><em>9</em> in the <em>next</em><em> </em><em>lower </em><em>number</em><em> </em>that <em>ends</em> in <em>0</em><em>0</em><em>0</em><em>0</em><em>.</em>

<em>for</em><em> </em><em>example</em><em>:</em>

265,427 rounded to the nearest ten thousand is 270,000

8 0

3 years ago