Hello from MrBillDoesMath!
Answer:
x = -3, 4
Discussion:
The zeroes of f(x) are the x values where
2x + 6 = 0 => x = -3
and
x - 4 = 0 => x = 4
Thank you,
MrB
Answer:
a
Step-by-step explanation:
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Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
Missing length = 20
Step-by-step explanation:
Ratio is 16/20=4/5
25×4/5=20
Answer:
97 and 1/8
Step-by-step explanation:
(4 + 7 + 5 + 5 + 2) + (14 5/8 + 14 3/4 + 14 7/8 + 15 + 15 1/8)
23 + (14 5/8 + 14 3/4 + 14 7/8 + 15 + 15 1/8)
23 + 74 1/8
97 and 1/8