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The point M is the midpoint of the line section PQ. Just a line fragment can have a midpoint. A line can't since it goes on uncertainly in the two bearings, thus has no midpoint. A beam can't on the grounds that it has just a single end, and henceforth no midpoint.
The Midpoint Formula works the very same way. In the event that you have to discover the point that is actually somewhere between two given focuses, simply normal the x-values and the y-values.
Triangle on the left: 30 60 90 right triangle
so ratio of short leg: long leg: hypo = x : x√3 : 2x
given hypo = 4√3
so
short leg = 4√3 / 2 = 2√3
long leg = 2√3 * √3 = 6
a = 6 and c = 2√3
triangle on the right is 45 45 90 right triangle
so ratio of leg: leg: hypo = x : x : x√2
from above you know a = 6 so d = a = 6
b = 6√2
Answer
a = 6, b = 6√2, c =2√3 and d = 6
we use divsion, 10 divided by 5 is 2, everyone get 2 yumy cupcakes.
Answer:
The answer would be C
Step-by-step explanation:
q equals cube root of 64
because if you want to get rid of cube. you take cube root on both side
(q^3)^1/3= (64)^(1/3)
q=64^(1/3)
4x+4= 6x -9 ( corresponding angle post.)
4x = 6x -13
-2x = -13
X= 13/2
Hope this helps!