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sergejj [24]
4 years ago
8

Please help C: eeeeeeeeeeeee

Mathematics
2 answers:
iVinArrow [24]4 years ago
8 0

Answer: X = 2

Step-by-step explanation:

so first you find out what 2x equals to which is

2x = 4

then you solve for x and the answer is 2  

x = 2

Klio2033 [76]4 years ago
4 0

Answer:

x = 2

Step-by-step explanation:

2x = 4

x = 2

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You have a bag full of apples. There are 8 Jonathan (red), 4 Granny Smith (green), and 5 Golden Delicious (yellow) apples in the
vredina [299]

Answer:

Step-by-step explanation:

There are 8 Jonathan (red), 4 Granny Smith (green), and 5 Golden Delicious (yellow) apples in the bag.

a) Select 3 apples with replacement. Find the probability that all there are green.

  • Given that we are taking all apples with replacement, the probability of getting a green apples remains the same in all 3 trials. Therefore the probability here is computed as:

  • = (Number of green apples/Total apples)
  • = (4/17)^3
  • = 0.0130

Therefore 0.0130 is the required probability here.

b) Select 3 apples with replacement. Find the probability that none are red

Probability that none are red is computed here as:

  • = (Number of non red apples/Total apples)
  • = (9/17)^3
  • = 0.14838

Therefore 0.14838 is the required probability here

c) Select 4 apples with replacement. Find the probability that you get at least 2 red apples

  • Probability that we get at least 2 red apples when 4 apples are drawn is computed here as:
  • = 1 - (Probability that no red apple is taken out when 4 apples are taken out + Probability that 1 red apple is taken out when 4 apples are taken out)
  • = 1 - 8C0 x 9C4 + 8C1 x 9C3 / 17C4
  • = 1 - 0.3353
  • = 0.6647

Therefore 0.6647 is the required probability here

d) Select 2 apples with replacement. Find the probability that the second apple is yellow given that the first apple is red.

  • Given that the first apple is red, we are left with 16 apples out of which 5 are yellow. Therefore the required probability here is computed as:
  • = 5/16
  • = 0.3125

Therefore 0.3125 is the required probability here

3 0
3 years ago
Could someone explain this to me?
Ilya [14]
This is a simple differentiation problem. Let's start by taking the derivative of both sides (with respect to x):
5y^4\frac{dy}{dx}+6y^2x+6x^2y\frac{dy}{dx}+20x^3 = 0

Simplify:
\frac{dy}{dx} (5y^4+6x^2y) + 6y^2x+20x^3 = 0

Solve for dy/dx:
\frac{dy}{dx} = \frac{-6y^2x-20x^3}{5y^4+6x^2y}

Now, plug in the given points:
\frac{dy}{dx} = \frac{-6(2)^2(-1)-20(-1)^3}{5(2)^4+6(-1)^2(2)} = \frac{24+20}{80+12}

Further simplification gives:
\frac{dy}{dx}|_{(2,-1)} =\frac{44}{92} =  \frac{11}{23}

So, your answer is 11/23 or B.
7 0
4 years ago
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