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Lemur [1.5K]
2 years ago
5

Angel and Jayden were at track practice. The track is 2/5 kilometers around.  Angel ran 1 lap in 2 minutes.  Jayden ran 3 laps

in 5 minutes. How far does Jayden run in one minute?
Mathematics
2 answers:
choli [55]2 years ago
7 0

Answer:

6/25 km in 1 min; or 0.24 km/min

Step-by-step explanation:

The info about Angel is not necessary.

Jayden runs 3 laps in 5 mins

Each lap is 2/5 km, so Jayden runs 3 x (2/5 km) in 5 min = 6/5 km in 5 min.

Distance = rate x time

6/5 km = rate (5 min)

We want to isolate r (rate), so divide both sides by 5 min

6/5 km ÷ 5 min = r

6/5 km (1/5 min) = r

6/25 km/min = r  (notice how the units worked out correctly to km/min)

So, Jayden runs 6/25 km in 1 min.

padilas [110]2 years ago
3 0

Answer:

6/25 miles km in a minute

Step-by-step explanation:

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Korvikt [17]

Answer:

D

Step-by-step explanation:

out of the choices

A) 2x-y=-2

3x+2y=-10

B) x+4y=3

2x+5y=3

C) 2x+3y=5

x-4y=-14

D) 3x+4y=15

x+y=5

only the system in D has a solution of x=5 and y=0

solve by substitution x+y=5 so x=5-y

plug into the other equation so 3(5-y)+4y=15

distribute 15-3y+4y=15 then minus 15 on both sides and combine like terms

so y=0 then put that value back into the other equation

so x+y=5 equals x+0=5 so x=5 this means the solution to the system of equations is the point (5,0)

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3 0
2 years ago
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In a class of 40 students, 5 like neither Nokia nor
Vikki [24]

Answer:

No student liked only Nokia

Step-by-step explanation:

The information can be illustrated as shown on the Venn diagram.

The number of students who liked only Nokia is x.

The sum of all regions in the Venn diagram should be 40.

We add all to get:

5 + 5 + 30 + x = 40

40 + x = 40

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8 0
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This is urgent, please answer!
In-s [12.5K]
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salantis [7]

Answer:

a) S = {1, 2, 3}

b) P(odd number) = \frac{2}{3}

c) No

d) Yes

Step-by-step explanation:

a) The sample space is the set of all possible outcomes. By definition, the elements of a set should not be repeated. Hence, the sample space S = {1, 2, 3}

However, the sample is not equiprobable because each element has different probabilities.

b) P(odd number) = \frac{number of odd digits}{number of faces}=\frac{4}{6}=\frac{2}{3}

Note that the odd numbers are 1 (on three faces) and 3 (on one face).

c) The fact the die has been biased does not change the possible outcomes. It only changes the probability of getting any given number.

d) Because the 3-face has been loaded, this probability changes. In fact, it is calculated thus:

Let's assume the probability for 1 or 2 is x. Then that of 3 is 2x(because it is twice the others). The sum of probabilities must be 1.

x+x+x+x+x+2x=1

7x=1

x=\frac{1}{7}

P(odd number) = 3\timesProb(1) + Prob(3)

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Vikki [24]
The answer c is not true
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