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umka21 [38]
4 years ago
15

Solve in 10seconds or less i will chose the best awnser if it's blank deleted question

Mathematics
1 answer:
Tpy6a [65]4 years ago
8 0

Answer:

5.35

Step-by-step explanation:

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4 years ago
The area of a rectangle is 45 cm2. Two squares are constructed such that two adjacent sides of the rectangle are each also the s
lorasvet [3.4K]

Answer:

The length of sides of one square is 5cm  and length of sides of another square is 9cm

Step-by-step explanation:

Let the length of rectangle be x and width of rectangle be y.

We have given,

Area of rectangle = 45 cm²

i.e. Area of rectangle = x·y = 45  or xy = 45   ---------(1)

Next, two squares are constructed from two adjacent sides of rectangle.

i.e Side length of one square will be x and side length of another square will be y.

Area of one square = x²

And area of another square = y²

According to problem,

Sum of area of two squares is 106 cm²

∴ x²+y² = 106   ---------------(2)

From equation (1) and (2) , we can find x and y.

xy = 45  or x = \frac{45}{y}  , Plug this in equation (2).

We get,

x² + y² = 106

or (\frac{45}{y} )^{2} + y^{2} =106

or \frac{45^{2} +y^{4} }{y^{2} } =106

or 45^{2} + y^{4} = 106y^{2}

On solving this equation we get ,

y²=81 or 25

or y = 9 or 5

for y =9 , x= \frac{45}{9} =5

or for y = 5 , x = \frac{45}{5} =9

Hence the length of sides of one square is 5cm  and length of sides of another square is 9cm

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3 years ago
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