Answer:
The probability that the web site is up is 0.84 = 84%.
Step-by-step explanation:
For each web server, there are only two possible outcomes. Either it is working, or it is not. The probability of a web server being working is independent of any other web server, which meas that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Either file server works with a probability of 0.6.
This means that 
Two servers.
This means that 
The probability that the web site is up is
At least one server working, which is:

In which


Then

The probability that the web site is up is 0.84 = 84%.