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valina [46]
4 years ago
13

A square ABCD has the vertices A(n, n), B(n, -n), C(-n, -n), and D(-n, n). Which vertex is in Quadrant IV?

Mathematics
1 answer:
Usimov [2.4K]4 years ago
4 0
I drew it out it should be d
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The length of a rectangle is 5 less than 3 times its width. The perimeter is
My name is Ann [436]

Answer:

The length is 28 and the width is 11

Step-by-step explanation:

To solve this problem, we can make the width as x.

Since the length is 5 less than 3 times the width, it's going to be 3x - 5

So now we've got the length and width, just need to find the perimeter, which is all the sides added up together. They already gave us the perimeter, so we just have to solve the equation:

2(3x - 5) + 2x = 78

6x - 10 + 2x = 78

8x - 10 = 78

8x = 88

x = 11

x = 11, but remember, x is the width, not the length. Since we already found what x is, we just have to plug it into the equation of:

3x - 5

3 × 11 - 5

33 - 5 = 28

Answer: Length = 28 (don't forget to add the unit if there is one)

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3 years ago
How do i solve this?
bixtya [17]

Answer:

5.x^8.y^3

Step-by-step explanation:

15.x^10.y^5.z^2 ÷ 3.x^2.y^2.z^2

= 15/3. x^(10-2). y^(5-2). z^(2-2)

= 5.x^8.y^3.z^0

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Answer:

3 {w}^{5}  \times  {7w}^{5}  \\  \\  = (3 \times 7)( {w}^{5}  \times  {w}^{5} ) \\  \\  = 21( {w}^{5}  \times  {w}^{5} )

from law of indices:

{x}^{a}  +  {x}^{b}  =  {x}^{(a + b)}

therefore:

= 21 \{ {w}^{(5 + 5)}  \} \\  \\  ={ \boxed{ 21 {w}^{10} }}

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Dennis_Churaev [7]

Answer:

del

Step-by-step explanation:

d

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3 years ago
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