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3 years ago

10

John is building a fence around his home currently has that measures 14 feet on each side but he wants to increase width of his

fence by x feet to have a rectangular fence that has an area of 280 square feet write an equation that can be used to find x. then Slove equation show your work a remember to include units

1 answer:

wlad13 [49]3 years ago

8 0

Answer:

Step-by-step explanation:

14

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What's the single exponent for K^8 x K^9

gregori [183]

K^8 • K^9 = K^(8+9) = K^17

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3 years ago

Using the approximation 3.14 for pi, what is the radius of a circle with circumference 69.1 m?

Nat2105 [25]

Answer:

11.0

Step-by-step explanation:

Circumfrence = 2 x pi x r.

making radius, r the subject of relation, you.get 11.003184713

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3 years ago

Read 2 more answers

The sum of two numbers is 52. The larger number is 8 more than the smaller number. What are the numbers?

iVinArrow [24]

Answer:

The smaller number is 22

The larger number is 30

Step-by-step explanation:

L + S = 52

L = S + 8

Set both equations equal to L.

S + 8 = -S + 52

+S +S

2S + 8 = 52

- 8 - 8

2S = 44

S = 22

To find the larger number, plug 22 in as S into the equations.

L = 30

3 0

3 years ago

If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal

lorasvet [3.4K]

Answer:

a

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

b

The probability is $P(Z > 2.5 ) = 0.0062097$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 800$

The variance is $var(x) = 1600 \ kg$

The range consider is $x_1 = 778 \ kg \ x_2 = 834 \ kg$

The value consider in second question is $x = 900 \ kg$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{var (x)}$

substituting value

$\sigma = \sqrt{1600}$

$\sigma = 40$

The percentage of a cucumber give the crop amount between 778 and 834 kg is mathematically represented as

$P(x_1 < X < x_2 ) = P( \frac{x_1 - \mu }{\sigma} < \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma } )$

Generally $\frac{X - \mu }{ \sigma } = Z (standardized \ value \ of \ X)$

So

$P(x_1 < X < x_2 ) = P( \frac{778 - 800 }{40} < Z< \frac{834 - 800 }{40 } )$

$P(x_1 < X < x_2 ) = P(z_2 < 0.85) - P(z_1 < -0.55)$

From the z-table the value for $P(z_1 < 0.85) = 0.80234$

and $P(z_1 < -0.55) = 0.29116$

So

$P(x_1 < X < x_2 ) = 0.80234 - 0.29116$

$P(x_1 < X < x_2 ) = 0.51118$

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

$P(X > x ) = P(\frac{X - \mu }{\sigma } > \frac{x - \mu }{\sigma } )$

substituting values

$P(X > x ) = P( \frac{X - \mu }{\sigma } >\frac{900 - 800 }{40 } )$

$P(X > x ) = P(Z >2.5 )$

From the z-table the value for $P(Z > 2.5 ) = 0.0062097$

7 0

3 years ago

Second Time Asking This:

sattari [20]

128 ÷3=42.66

it doesn't say if they have to pay the money back but if they do it's

128-35= 43

43÷3= 14.33

8 0

3 years ago