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marishachu [46]
3 years ago
7

Answer ASAP with explanation and will give brainlist

Mathematics
1 answer:
finlep [7]3 years ago
7 0

Answer:

34.75x

Step-by-step explanation:

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Please help me with this problem.
Alik [6]

We're going to use the equation given but let's first make sure we understand what the equation IS saying:

Area of a kite= [(1st diagonal) × (2nd diagonal)]/2

Now, let's find the 2 diagonals. In the case of kite shapes one of the diagonals is the line that goes from W to Y and the other is the line going from X to Z. In a kite they will always cross (no matter their lengths).

Now that we know the diagonals we can add the lengths that are given for each line to know what to multiply.

Line W to Y: 20+12= 32

Line X to Z: 12+12= 24

Now let's plug these numbers into the equation (it doesn't matter the order of the diagonals because we're just gonna be multiplying them either way!)

So...

(32×24)/2= 384 units squared (because it is area)

8 0
3 years ago
What is 90.95 rounded to the nearest whole number
Kamila [148]
90.95 rounded to the nearest whole # is 91

8 0
4 years ago
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Ruby uses 7.2 pints of blue paint and white paint to paint her bedroom walls. 3/4 of this amount is blue paint, and the rest is
Nuetrik [128]

Answer:

1 4/5 or 1.8 pints are white

Step-by-step explanation:

1/4 of 7 1/5 = 1/4 x 36/5 = 36/20 or 9/5, which is 1 4/5

5 0
3 years ago
Please help <br><br><br> will mark brainlist
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ANSWER:

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(5,-10)

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(15,-6)

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(15,-15)

4 0
3 years ago
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Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
3 years ago
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