Question

The perimeter of a rectangle is twice the sum of its length and it’s width . The perimeter is 22 meters and I it’s length is 2 meters more then twice it’s width. What’s its length?

Answer 1

Answer:

The length of this rectangle is 8m.

Step-by-step explanation:

The problem states that the perimeter of a rectangle is twice the sum of its length and it’s width. So

$P = 2*l + 2*w$

The problem also states that the perimeter is 22 meters. So:

$P = 22$

$2l + 2w = 22$.

Also, it states that I is the length and it is 2 meters more then twice it’s width. So

$l = 2w + 2$

What’s its length?

$P = 22$

$2l + 2w = 22$

$2(2w+2) + 2w = 22$

$4w + 4 + 2w = 22$

$6w = 22 - 4$

$6w = 18$

$w = \frac{18}{6}$

$w = 3$

The width is 3m. The length is in function of the width, so:

$l = 2w + 2$

$l = 2*3 + 2$

$l = 8m$

The length of this rectangle is 8m.