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nata0808 [166]
3 years ago
15

What is the area of the figure

Mathematics
1 answer:
Ronch [10]3 years ago
6 0
THE ANSWER IS 189
BECAUSE FIRST YOU HAVE TO FIND THE AREA OF THE WHOLE FIGURE WHICH WAS A RECTANGLE AND THE FORMULA IS A= L*W AND THE ANSWER WAS 192 , NOW YOU HAVE TO SUBTRACT THE ARE OF THE TRAPIZIOD AND THE FORMULA IS B1+B2/2=A AND THE ANSWER TO THAT WAS 3 ,;LAST YOU SUBTRACT 192-3 AND THE FINAL ANSWER IS 189
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Which outcome is most likely after a die is rolled?
muminat

Answer:

a number less then 6 is the anser so the 1st one

5 0
2 years ago
On Friday, a local hamburger shop sold a combined total of 309 hamburgers and cheeseburgers. The number of cheeseburgers sold wa
cupoosta [38]
Divide 309 by 3. You should get 103 (hamburgers). if you multiply that by 2 you will get 206 (cheeseburgers). Add the two together you get the total which was 309 originally.
103 hamburgers and 206 cheeseburgers.
3 0
3 years ago
8th one answer this pls​
GuDViN [60]

Answer:

terminating

Step-by-step explanation:

if the given fraction is terminating then prime factors of denominator should be 2^n x 5^m where m and n are whole number

5=1x5=2^0x5^1

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8 0
3 years ago
Marine biologists have been studying the effects of acidification of the oceans on weights of male baluga whales in the Arctic O
PSYCHO15rus [73]

Answer:

c. 61.25 kg

Step-by-step explanation:

The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean.

a. 15.31 kg

b. 51.40 kg

c. 61.25 kg

d. 80.49 kg

Margin of Error Formula= z × Standard deviation/√n

95% confidence interval = 1.96

Standard deviation = 125kg

n = 16 samples

Margin of error= 1.96 × 125/√16

= 1.96 × 125/4

= 245/4

= 61.25kg

The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean is 61.25kg

6 0
3 years ago
What factor does the width of the peak of a normal curve depend on?
Katyanochek1 [597]
The width of a peak depends on A. Standard deviation
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3 years ago
Read 2 more answers
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