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Marina CMI [18]
3 years ago
12

What percent of 88 is 132?

Mathematics
1 answer:
sp2606 [1]3 years ago
3 0
150% i believe. If im wrong i apologize.
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A line passes through the points (-6,4) abd (-2,2) which is the equation of the line
krek1111 [17]
Bibby
m=y2−y1x2−x1=15−75−1=84=2y−y1=m(x−x1)⟺(x1,y1)=(1,7)y−7=2(x−1)y−7=2x−2y=2x−2+7 y=2x+5
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3 years ago
shayla is financing a house for $126,750. She has to pay $450 plus 1.15% for a brokerage fee. How much are the mortgage brokerag
ANEK [815]
Answer: $1,907.63

Explanation:

It is stated in the problem that the brokerage fee is $450 plus 1.15% (meaning 1.15% of $126,750). Hence the brokerage fee is computed as follows
  
(Brokerage fee) = $450 + (1.15% of $126,750)
                          = $450 + (0.0115)($126,750) 
                          = $450 + $1,457.625
                          = $1,907.625

Since there is no half cents today, we round-off the brokerage fee to the nearest cent. Hence the brokerage fee is $1,907.63.

Note: In the computation of brokerage fee, we need to change 1.15% to  decimal.   
7 0
2 years ago
Fiona divided 3x2 + 5x – 3 by 3x +2. The expression represents the remainder over the divisor. x + 1 + What is the value of a?
grigory [225]
                    x + 1
         __________
3x+2 I 3x² +5x -3
           3x² +2x
           ----------
                    3x -3
                    3x+2
                    --------
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8 0
3 years ago
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A total of 75 cookies and cakes were donated for a bake sale to raise money for the football team. There were four times as many
MArishka [77]

Answer:

60

Step-by-step explanation:

15*4 = 60

15+60= 75

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2 years ago
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A gardener wants to know if soaking seeds in water before planting them increases the proportion of seeds that germinate. To inv
juin [17]

Answer:

d. I and III only

Step-by-step explanation:

I. The seeds should be randomly assigned to a treatment.

III. The number of successful seeds and unsuccessful seeds in each group should be at least 10.

The distribution of difference between two sample proportions :

Given :

Proportion 1 = P1 ;

Proportion 2 = P2 ;

Sample assignment for both samples 1 and 2 into the different treatment groups should be randomized, that is a simple random sampling of subjects into the treatment and control group. The sample design for difference between two sample proportions should be independent.

Finally each of the two proportions P1 and P2 should record a minimum of 10 successes and 10 non - successful Occurrences.

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